TP Les fonctions

Fonction affine⚓︎

Écrire le code d'une fonction f qui a tout nombre x associe -4x + 7.

Évaluations restantes : 5/5

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Somme⚓︎

Écrire une fonction addition qui prend deux nombres en paramètre et retourne leur somme.

Évaluations restantes : 5/5

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Pair ou impair⚓︎

Créer une fonction est_pair qui prend un entier et retourne True s’il est pair, sinon False.

Évaluations restantes : 5/5

.128013itadvn2Swbcy1: f-up0)_el%ohrP=s(/mgk050e0x0c0d0b0y0F0p0l0y0d0F0F0E010c0b0t010406050F0s0I0I0d0C0m040i0A0y0s0#0A0g050H0,0.0:0=0*0t0405150~180H150*0e0b0f0T0V0X0Z0V0g0J0s0d0J0x0r0t0m0c0B0|0p0B0b0J0B0y1A0B0c0(050O0k0y0x1h0W0Y011z1B1D1B0c1J1L1H0c0C161v0T0^0F0t0d0g0Z0h011N1j010q0Q0x0g0d0I0x1H1)1+1:1P1?1L1_1{0(0a0p0D0C0A0t0A0F0b0{0g0p0M1%0C0C0x0l2g0~1~0g160H1v2t1Z1#1!1I0e201k0b0g1^2d1H1e1g0U1O2D2F0g0A2J1H0t2m162r2t2W0+1*2h2L1;2P0C0/0y1H0d1y2m0q0Z030w0w0l2Q0x1D2O0A0r0h0r0n0(0n0~0d2X2!0)2Z1 2$1P2(2*2,2.0x2:012=2@2_2{2G2~2~0(0h34361+2t2T0x2t2J2w0e1#2B3b0Z2^0M2I1f163x2V372q3O3H3y392h0b0e0Z2?2r3p31162-3V3X3l0M3n2P3!1/240x3)3R3,2}2 3#3t3T2C010K0(0M0q3P3v3|3F010j0(0p432s451i3c0q0(0x0F0c0w1*0b0C4b3N3a4e0Z0%040G4p4d2M010g0(0}0 3O2r3}4u0v0o4p0*4E444G3(013Y2!3p1.3$0p4Q2?3?2E3o2 1.0p3:3=3m4#3-4%1H0H350p4?4a4G463 042m0c0s0C4D2W4^2!3}4B045137534r4z0A0(0z4p5a2#4s010I0b3r5g4y1;5d040E0E5o4_5j5l0(0u4L4x0H3R3w2U0~3A0~0c3C5J2z2u0d1K3S0H3A4M0M0O0Q0F04.

Compter les voyelles dans une phrase.⚓︎

Compléter le code d'une fonction compter_voyelles qui prend une chaîne de caractères et retourne le nombre de voyelles (a, e, i, o, u, y) (majuscule/minuscule).

Évaluations restantes : 5/5

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Tester si un nombre est premier.⚓︎

Écrire une fonction est_premier qui prend un entier et retourne True s’il est premier, sinon False.

Évaluations restantes : 5/5

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Noircir un texte⚓︎

Avant de rendre public des dossiers sensibles, il arrive que certains organismes les « anonyment » en entier ou partiellement.

Dans le cadre de cet exercice, nous ne programmons qu'une version simpliste : « noircir » un texte consiste à remplacer toutes les caractères alphabétiques par un caractère occultant, comme par exemple ▮.

Le texte L'espion était J. Bond devient alors ▮'▮▮▮▮▮▮ ▮▮▮▮▮ ▮. ▮▮▮▮.

On demande d'écrire la fonction noircir qui prend en argument une chaîne de caractères texte ainsi que le caractère occultant noir et renvoie le même texte « noirci » du début à la fin.

Astuce

Si s est une chaîne de caractères, l'instruction s.isalpha() renvoie True si s n'est composée que de caractères alphabétiques.

Ainsi "é".isalpha() est évalué à True, "Bonjour !".isalpha() est évalué à False.

Attention

Python interdit de modifier les chaînes de caractères. Vous devez donc en créer une nouvelle.

Pour cela, on utilise l'opérateur + qui permet de concaténer deux chaînes, ey donc d'ajouter un caratère à la fin d'une chaîne.

texte = '' + 'e'

ou

texte = 'salu' + 't'

Exemples

>>> noircir("", "*")
''
>>> noircir("L'espion était J. Bond", "▮")
"▮'▮▮▮▮▮▮ ▮▮▮▮▮ ▮. ▮▮▮▮"
>>> noircir("L'espion était J. Bond", "_")
"_'______ _____ _. ____"
>>> noircir(";-)", "▮")
';-)'

Évaluations restantes : 5/5

.128013it3a;dv,n2.S5wbcy+14q: f-up8)_9eklohxrP=s6(/mg7050g0G0c0e0b0I0P0x0q0I0e0P0P0O010c0b0B010406050P0A0T0T0e0M0r040m0J0I0A0:0J0j050S0`0|0~100^0B04051g191j0S1g0^0g0b0h0(0*0,0.0*0j0U0A0e0U0G0z0B0r0c0K170x0K0b0U0K0I1L0K0c0?050Z0p0I0G1s0+0-011K1M1O1M0c1U1W1S0c0M1h1G0(130P0B0e0j0.0k011Y1u010y0#0G0j0e0T0G1S1@1_1~1!211W24260?0a0x0N0M0J0B0J0P0b160j0x0X1=0M0M0G0q2r19290j1h0S1G2E1.1:1/1T0g2b1v0b0j232o1S1p1r0)1Z2O2Q0j0J2U1S0B2x1h2C2E2+0_1^2s2W1 2!0M0}0I1S0e1J2x0y0.030E0E0q2#0G1O2Z0J0z0Q0z0t0?0t190e2,2/0@2.2a2;1!2?2^2`2|0G2~01303234362R390z1|040k3f3h1_3j2C2N013o0e2_1h2{0K2}2 31330X3y2!3A0d0?0d3F2B3i0^3J3m0.3M3O053Q3S3u3U3x2P3z3a0u0?0u3%1a3)3k2:1t3n0J2@3N3q3R3s3T3w3W3_3Y3a0n0?0n3 2+3*2/3K3.493=3v3V354f383a0Q0?0Q4l413+443-463p3P3r3t4t3^373A0V0?0V4C3H4n3l4F3L4H484J4a4L3@4e4O3a0C0?0C4T2D4V432X4Y473/3;4b3?4d4v4*0z0F0?0F4/2E2(0G2E2U2H0g1:2M3,014u2T1q1h562*3i3(3H054u5l2a0b0g0.312C3A3c4J5t5v4}3X4x3b1}2f0G5C4u5E5y1S0S3g423K0H0?0X0y5n2D5R5e0o0?0x5X5r4=2=0y0?2!0b0M0q5/5(5Z4X0=040R5?4E4?0j0?0c0G0L615|4o5e5_0i5(5%5}2=5-0J5=405o6c1!5_0D0w5(0^6h5Y3J5B015w2/3A3C3:0x6t4(4~3`3B5H255J6u5D4w6x5O3g0x6P6b664X5 042x0`0I0Z0c6a5@4?0J0?0O6#6j0.0P3C020v0A0J0c0f6:6=6@6o655s5u6J5x3a3!5A6 6C5M726G265K4N6E733F6Q6R4W4?5T040y466+6S5~0?0q0~0e2z0G2x7o7i1 0J5#042P7y5*3n6062646q5)3K5_6n7L6p2-6s750E710z3|747b4)6E3|0x5I7!6D4g7X6N047g7g6$1 7k0b5W7L7h7G3-7r7t7v7x7L7=1!6(040l6}7|3L0?0b0P3N0B0K0e887N0?0R6m6|827T5C7W4i7Z6J5L6L4h796I768w0z8s7f7:8F837}6V0G6X6Z7F3K850s6*7`8H8a045.0M8n7S4o6B7V6w4y3q8#8v4 4z7(6H7*77397.8F6P8T7k350P0G8i670?7P4m8i8#7W4Q8t8A4 4Q8.7a8u7c7,968E8@6Q8T6U6W0A6Y0e6!8S6,018P8R2+7{4p7~0M7u6181928o8!7U7W4,976K4 4,9b8z9L6E9J3F7R5m8p708%508)7U8+6E519O8:8B512E6O9j9s7k2x0c0A0M189r7p6d8J8L9p8Y5m0S5q1k2)1959190c5ba82K2F0e1V57a65i6p0X0Z0#0P04.

La suite de Syracuse⚓︎

Pour construire la suite de Syracuse d'un entier $n$ strictement positif, on répète la transformation suivante :

Si $n$ est pair, on le divise par $2$ ;
Sinon $n$ devient $3n+1$.

On admet que, quel que soit l'entier $n$ choisi au départ, la suite finit toujours par atteindre la valeur $1$. On convient donc d'interrompre les transformations lorsque l'on a atteint la valeur $1$.

Ainsi, en prenant de $n=3$, on obtient :

\[3 \longrightarrow 10 \longrightarrow 5 \longrightarrow 16 \longrightarrow 8 \longrightarrow 4 \longrightarrow 2 \longrightarrow 1\]

On rappelle que n % 2 renvoie le reste dans la division de n par 2. Si ce reste est nul, c'est que n est un nombre pair.

Longueur du vol

On a admis que, quel que soit l'entier $n$ choisi, ce processus de calcul finissait toujours par atteindre $1$. Par exemple en partant de la valeur $3$, il y a $7$ transformations avant d'atteindre $1$.

Ce nombre de transformations nécessaires est appelé « longueur du vol » de l'entier $n$.

Écrire une fonction longueur_vol qui prend en paramètre un entier n strictement positif et renvoie la longueur du vol de cet entier.

Exemple

>>> longueur_vol(3)
7
>>> longueur_vol(7)
16
>>> longueur_vol(1)
0

Évaluations restantes : 5/5

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